grep print only capture group

## Short answer:
$ grep -oP 'stuff before your match\Kyour match(?=stuff after your match)'

## Explanation:

# GNU grep has the -P option for perl-style regexes, and the -o option to print
# only what matches the pattern.

# These can be combined by using perl-style look-around assertions (described
# under Extended Patterns in the perlre manpage) to not count the beginning and
# end of the regex as part of the match that -o will grab.

# Prefix your match pattern with \K to exclude the beginning. \K is the shorter
# (and more efficient) form of (?<=pattern), a zero-width look-behind assertion
# that means, "Matches must come after this."

# Put anything following your match pattern within (?=pattern). This is a zero-
# width look-ahead assertion that means, "Matches must be followed by this."

# set up a test file for reference
$ echo '
foobar bash 1
bash
foobar happy
foobar
foo bar
foo 123 bar
foo abc bar
' > test.txt

$ grep -oP 'foobar \K\w+' test.txt
# bash
# happy

$ grep -oP 'foo \K\w+(?= bar)' test.txt
# 123
# abc

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3.8

Carmita Kelley 70 points

                                    # matches and returns b
$ echo &quot;abc&quot; | grep -oP &quot;a\K(b)(?=c)&quot; 
b 
# no match
$ echo &quot;abc&quot; | grep -oP &quot;z\K(b)(?=c)&quot;
# no match
$ echo &quot;abc&quot; | grep -oP &quot;a\K(b)(?=d)&quot;

Thank you! 5

3.8 (5 Votes)

4.16

Jwarren 90 points

                                    # matches and returns b
$ echo &quot;abc&quot; | grep -oP &quot;a\K(b)(?=c)&quot; 
b 
# no match
$ echo &quot;abc&quot; | grep -oP &quot;z\K(b)(?=c)&quot;
# no match
$ echo &quot;abc&quot; | grep -oP &quot;a\K(b)(?=d)&quot;

Thank you! 7

4.16 (19 Votes)

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