tkinter filedialog filename
from tkinter import filedialog
# Where it open to. # What the window is called. # What file types the user can choose between. first one is the defualt. (("what ever", "*.format"), ("what ever 2", "*.format2"))
filedialog.askopenfilename(initialdir=os.path.normpath("C://"), title="Example", filetypes =(("PNG", "*.png"),("JPG", "*.jpg"),("All Files","*.*")))
3.5
4
def open_file():
file = askopenfile(mode='r', filetypes=[
('Text files', '*.txt'), ('CSV Files', '*.csv')])
if file is not None:
print(file.name.split("/")[-1]) # this will print the file name
btn = Button(root, text='Open', command=lambda: open_file())
btn.pack(side=TOP, pady=10)
Thank you!
4
0
4.5
4
from tkinter import filedialog
# Where it open to. # What the window is called.
folder = filedialog.askdirectory(initialdir=os.path.normpath("C://"), title="Example")
Thank you!
4
0
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