random hex value generator python
import random
r = lambda: random.randint(0,255)
print('#%02X%02X%02X' % (r(),r(),r()))
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import random
random_number = random.randint(0,16777215)
hex_number = str(hex(random_number))
hex_number = f"#{hex_number[2:]}"
print(hex_number)
'''
Explanation -
In this code at first, we import the random library to work.
Then we generate a random integer decimal number by using random.randint()
function, which must be in between lower value 0 and upper value 16777215.
Then we convert the decimal number into hexadecimal value. And we convert the
data type of the hexadecimal value into a string data type to perform any
string operations. As we know in python, after conversion any int value
into hexadecimal, its starts with 0x in the hexadecimal value, to remove 0x,
we take the string value after 2nd position. Finally, we get a Hex code. Then
simply we add a ‘#’ character at the beginning of the hex code. there are alot
of ways to print '#' with hex number i used f string to do this. And Print it.
'''
Thank you!
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