python sort dictionary by value descending
Python Code:
import operator
d = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
print('Original dictionary : ',d)
sorted_d = dict(sorted(d.items(), key=operator.itemgetter(1)))
print('Dictionary in ascending order by value : ',sorted_d)
sorted_d = dict(sorted(d.items(), key=operator.itemgetter(1),reverse=True))
print('Dictionary in descending order by value : ',sorted_d)
Sample Output:
Original dictionary : {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
Dictionary in ascending order by value : {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Dictionary in descending order by value : {3: 4, 4: 3, 1: 2, 2: 1, 0: 0}
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1. new_list = sorted(old_list, key=lambda k: k['key'], reverse=True)
/*use reverse=False for ascending order*/
Thank you!
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