python sort dict by key
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)
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d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)
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A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}
output:
{-1: 4, 1: 2, 4: -20}
Thank you!
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3.71
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newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
Thank you!
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#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples
Thank you!
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