python sort array of dictionary by value

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

3.78
2
FuzzyWuzzy 105 points

                                    my_list = sorted(my_list, key=lambda k: k['name'])

3.78 (9 Votes)
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