python binary string to int
def getBaseTen(binaryVal):
count = 0
#reverse the string
binaryVal = binaryVal[::-1]
#go through the list and get the value of all 1's
for i in range(0, len(binaryVal)):
if(binaryVal[i] == "1"):
count += 2**i
return count
0
3
# Convert integer to binary
>>> bin(3)
'0b11'
# Convert binary to integer
>>> int(0b11)
3
Thank you!
3
0
3.4
8
>>> int('11111111', 2)
255
Thank you!
8
0
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