how to check if a number is armstrong in python
num = 1634
# Changed num variable to string,
# and calculated the length (number of digits)
order = len(str(num))
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** order
temp //= 10
# display the result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
4
10
# Python program to check if the number is an Armstrong number or not
# take input from the user
num = int(input("Enter a number: "))
# initialize sum
sum = 0
# find the sum of the cube of each digit
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** 3
temp //= 10
# display the result
if num == sum:
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
Thank you!
10
4
(10 Votes)
0
4
2
# Program to check Armstrong numbers in a certain interval
lower = 100
upper = 2000
for num in range(lower, upper + 1):
# order of number
order = len(str(num))
# initialize sum
sum = 0
temp = num
while temp > 0:
digit = temp % 10
sum += digit ** order
temp //= 10
if num == sum:
print(num)
Thank you!
2
4
(2 Votes)
0
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