format timedelta python
import datetime
start = datetime.datetime(2009,2,10,14,00)
end = datetime.datetime(2009,2,10,16,00)
delta = end-start
print(str(delta))
# prints 2:00:00
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def strfdelta(tdelta, fmt):
d = {"days": tdelta.days}
d["hours"], rem = divmod(tdelta.seconds, 3600)
d["minutes"], d["seconds"] = divmod(rem, 60)
return fmt.format(**d)
Thank you!
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