finding odd even python
# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.
num = int(input("Enter a number: "))
if (num % 2) == 0:
print("{0} is Even".format(num))
else:
print("{0} is Odd".format(num))
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num = int(input("Enter a Number:"))
if num % 2 == 0:
print(num , "is even")
else:
print(num , "is odd")
Thank you!
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mynumber = int(input("Enter number")) # Ask an integer number to the user
if mynumber % 2 == 0: # % = modelo, It is equal to the rest of the division
print(mynumber, "is an even number")
else: # The rest of 7 / 2 is 2.5, not 0
print(mynumber, "is an odd number")
Thank you!
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4.13
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number = int(input("Write a number:- "))
if number%2 == 0:
print("Even number")
else:
print("odd number")
Thank you!
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n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")
Thank you!
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def oddEvenCheck(n):
if (n%2) == 0:
print(n,' is even’)
else :
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