Find the second largest number in a list
def second_largest(numbers):
if (len(numbers)<2):
return
if ((len(numbers)==2) and (numbers[0] == numbers[1]) ):
return
dup_items = set()
uniq_items = []
for x in numbers:
if x not in dup_items:
uniq_items.append(x)
dup_items.add(x)
uniq_items.sort()
return uniq_items[-2]
print(second_largest([1,2,3,4,4]))
print(second_largest([1, 1, 1, 0, 0, 0, 2, -2, -2]))
print(second_largest([2,2]))
print(second_largest([1]))
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