strtol c

// definition: long int strtol (const char* str, char** endptr, int base);

/* strtol example */
#include <stdio.h>      /* printf */
#include <stdlib.h>     /* strtol */

int main ()
{
  char szNumbers[] = "2001 60c0c0 -1101110100110100100000 0x6fffff";
  char * pEnd;
  long int li1, li2, li3, li4;
  li1 = strtol (szNumbers,&pEnd,10);
  li2 = strtol (pEnd,&pEnd,16);
  li3 = strtol (pEnd,&pEnd,2);
  li4 = strtol (pEnd,NULL,0);
  printf ("The decimal equivalents are: %ld, %ld, %ld and %ld.\n", li1, li2, li3, li4);
  return 0;
}

4
6

                                    long strtol( const char * theString, char ** end, int base ); 

4 (6 Votes)
0
3.5
4
Jayden Kim 110 points

                                    char *strncpy(char *dest, const char *src, size_t n)

3.5 (4 Votes)
0
4.14
7

                                    # **strtol** | string to long integer | c library function
# EX.
# include &lt;stdlib.h&gt; // the library required to use strtol

int main() {
    const char str[25] = &quot;   2020 was garbage.&quot;;
    char *endptr;
    int base = 10;
    long answer;

    answer = strtol(str, &amp;endptr, base);
    printf(&quot;The converted long integer is %ld\n&quot;, answer);
    return 0;
}

# ignores any whitespace at the beginning of the string and
# converts the next characters into a long integer.
# Stops when it comes across the first non-integer character.

long strtol(const char *str, char **endptr, int base)

# str &minus; string to be converted.

# endptr &minus; reference to an object of type char*, whose value is set 
# to the next character in str after the numerical value.

# base &minus; This is the base, which must be between 2 and 36 inclusive,
# or be the special value 0.

4.14 (7 Votes)
0
4
17
Cloudpattern 120 points

                                    #include &lt;stdio.h&gt;
#include &lt;stdlib.h&gt;

int main () {
   char str[30] = &quot;2030300 This is test&quot;;
   char *ptr;
   long ret;

   ret = strtol(str, &amp;ptr, 10);
   printf(&quot;The number(unsigned long integer) is %ld\n&quot;, ret);
   printf(&quot;String part is |%s|&quot;, ptr);

   return(0);
}

4 (7 Votes)
0
4
10

                                    int my_strlen(char *str) {
  int i = -1;
  
  while (str &amp;&amp; str[++i]);
  return (i);
}

4 (10 Votes)
0
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