Rotation of array in C++

// C program to rotate an array cyclically

#include <stdio.h>

void rightRotateByOne(int arr[], int n) //function for cyclically rotating an array once
{
   int x = arr[n-1], i;
   for (i = n-1; i > 0; i--)
      arr[i] = arr[i-1];
   arr[0] = x;
}

int main()
{int t;
scanf("%d",&t);//number of test cases
int p;
for(p=0;p<t;p++){
    int n,i,k;
    scanf("%d %d",&n,&k); // n--> size of array ; k--> number of rotations
    int arr[n];
    k=k%n;
    for(i=0;i<n;i++){
        scanf("%d",&arr[i]);
    }
int j;
 for(j=0;j<k;j++) //cyclically rotating an array k times
{rightRotateByOne(arr, n);}


    for (i = 0; i < n; i++){
        printf("%d ", arr[i]);}
        printf("\n");}

    return 0;
}

3.57
7
Naigel 80 points

                                    List&lt;int&gt; iList = new List&lt;int&gt;(); 

    private void shift(int n)
    {
        for (int i = 0; i &lt; n; i++)
        {
            iList.Add(iList[0]);
            iList.RemoveAt(0);
        }


    }

3.57 (7 Votes)
0
4.67
3

                                    Input arr[] = [1, 2, 3, 4, 5, 6, 7], d = 2, n =7
1) Store the first d elements in a temp array
   temp[] = [1, 2]
2) Shift rest of the arr[]
   arr[] = [3, 4, 5, 6, 7, 6, 7]
3) Store back the d elements
   arr[] = [3, 4, 5, 6, 7, 1, 2]

4.67 (3 Votes)
0
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