how to print the elements of a linked list in c
typedef struct node{
int value; //this is the value the node stores
struct node *next; //this is the node the current node points to. this is how the nodes link
}node;
void printList(node *head){
node *tmp = head;
while(tmp != NULL){
if(tmp->next == NULL){
printf("%d", tmp->value);
}
else{
printf("%d, ", tmp->value);
}
tmp = tmp->next;
}
}
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