C Programming to swap two variables
#include <stdio.h>
#include <stdlib.h>
int main()
{
//initialize variables
int num1 = 10;
int num2 = 9;
int tmp;
//create the variables needed to store the address of the variables
//that we want to swap values
int *p_num1 = &num1;
int *p_num2 = &num2;
//print what the values are before the swap
printf("num1: %i\n", num1);
printf("num2: %i\n", num2);
//store one of the variables in tmp so we can access it later
//gives the value we stored in another variable the new value
//give the other variable the value of tmp
tmp = num1;
*p_num1 = num2;
*p_num2 = tmp;
//print the values after swap has occured
printf("num1: %i\n", num1);
printf("num2: %i\n", num2);
return 0;
}
4.22
9
#include <stdio.h>
int main()
{
int x = 20, y = 30, temp;
temp = x;
x = y;
y = temp;
printf("X = %d and Y = %d", x, y);
return 0;
}
Thank you!
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2022-03-27 22:30:45
Problem Statement Print the following output: \ Input Format IN Output Format \
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