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TypeScript 2021-12-23 18:11:22
script to see what tkinter fonts installed on system
from tkinter import * from tkinter import font root = Tk() root.title('Font Families') fonts=list(font.families()) fonts.sort() def populate(frame): '''Put in the fonts''' listnumber = 1 for item in fonts: label = "listlabel&quo... Add solution -
Javascript 2021-12-23 17:08:22
sort object alphabetically javascript
//Sort object by v1 property alphabetically (case insensitive) let objArray= [ {v1:"Bee", v2: 2}, {v1:"Apple", v2: 8}, {v1:"bat", v2: 4}, ]; let sortedArray= objArray.sort(function(a, b) { return a.v1.localeCompare... Add solution -
Javascript 2021-11-23 00:10:04
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution -
Javascript 2021-11-23 00:08:32
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution -
Javascript 2021-11-23 00:08:19
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution -
Javascript 2021-11-23 00:04:43
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution -
Javascript 2021-11-23 00:01:27
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution -
Javascript 2021-11-22 23:55:52
sort objects in an array
const books = [ {id: 1, name: 'The Lord of the Rings'}, {id: 2, name: 'A Tale of Two Cities'}, {id: 3, name: 'Don Quixote'}, {id: 4, name: 'The Hobbit'} ] books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0)); Add solution
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