Write a function digitsum that calculates the digit sum of an integer. The digit sum of an integer is the sum of all its digits.
#include <stdio.h>
int getSum(unsigned long long n) {
int sum = 0;
for (; n; n /= 10)
sum += n % 10;
return sum;
}
int main(){
printf("Sum of digits = %d\n", getSum(555));
}
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0
0
def getSum(n)
n.digits.sum
end
print "Sum of digits = ", getSum(555);
Thank you!
0
0
0
3.89
8
function digSum(n) {
let sum = 0;
let str = n.toString();
console.log(parseInt(str.substring(0, 1)));
for (let i = 0; i < str.length; i++) {
sum += parseInt(str.substring(i,i+1));
}
return sum;
}
Thank you!
8
3.89
(9 Votes)
0
5
1
function digits(num){
let numArray = num.toString().split('');
let sumArray = [];
for (let i = 0; i < numArray.length; i++) {
for (let j = i+1; j < numArray.length; j++) {
let sum;
sum = Number(numArray[i]) + Number(numArray[j]);
sumArray.push(sum);
}
}
return sumArray;
}
Thank you!
1
5
(1 Votes)
0
3.67
6
def sum_of_digits(n):
sum = 0
while (n != 0):
sum = sum + int(n % 10)
n = int(n/10)
return sum
Thank you!
6
3.67
(6 Votes)
0
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