unique elements in array java

                                    int [] arr = {1,1,1,2,2,2,3,3,3,4,4,5,5,6,7,8,};

for (int j= 0; j < arr.length; j++){
int count1 = 0; // to find out how many time value is appeared in the arry
for (int i = 0; i < arr.length; i++){
     if(arr[i] == arr[j] ) {    
    // if(arr[i] == 1 ) { once boyleydi ikinci for gelince soldaki oldu
      count1++; // arraydeki harfleri tek tek saymak icin
  }
 }
    if(count1 == 1 ){
    System.out.print(arr[j]+" ");// 6 7 8 uniqe
 }

                                    import java.util.ArrayList;

public class UniqueNumbersInArray {

    public static void main(String[] args) {


    int arr[] = { 4,5,5,4,5,6,5,8,4,7};

        ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
        for (int i = 0; i < arr.length; i++) {

            int k = 0;
            if (!uniqueArr.contains(arr[i])){
                uniqueArr.add(arr[i]);
                k++;

                for (int j = i; j < args.length ; j++) {
                    if (arr[i]==arr[j]){
                        k++;
                    }
                }

                System.out.println(arr[i]);
                System.out.println(k);
            }

        }
    }
}