Second Highest Salary

                                    SELECT MAX(salary) AS SecondHighestSalaryFROM EmployeeWHERE salary != (SELECT MAX(salary) FROM Employee)

                                    SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);

                                    /* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
    (
        select max(sal) from emp where sal <
            (select max(sal) from emp)
    )
----------------------------------------------- option 2
select *
from 
(
    select ename, sal, dense_rank() over(order by sal desc) rank
    from emp
)
where rank =2;