Determine the percentage of the file uploaded to the server using php
$(function() {
var bar = $('.bar');
var percent = $('.percent');
var status = $('#status');
$('form').ajaxForm({
beforeSend: function() {
status.empty();
var percentVal = '0%';
bar.width(percentVal);
percent.html(percentVal);
},
uploadProgress: function(event, position, total, percentComplete) {
var percentVal = percentComplete + '%';
bar.width(percentVal);
percent.html(percentVal);
},
complete: function(xhr) {
status.html(xhr.responseText);
}
});
});
<form action="file-echo2.php" method="post" enctype="multipart/form-data">
<input type="file" name="myfile"><br>
<input type="submit" value="Upload File to Server">
</form>
<div class="progress">
<div class="bar"></div >
<div class="percent">0%</div >
</div>
<div id="status"></div>
3.86
7
$.ajax({
xhr: function() {
var xhr = new window.XMLHttpRequest();
xhr.upload.addEventListener("progress", function(evt) {
if (evt.lengthComputable) {
var percentComplete = evt.loaded / evt.total;
percentComplete = parseInt(percentComplete * 100);
console.log(percentComplete);
if (percentComplete === 100) {
}
}
}, false);
return xhr;
},
url: posturlfile,
type: "POST",
data: JSON.stringify(fileuploaddata),
contentType: "application/json",
dataType: "json",
success: function(result) {
console.log(result);
}
});
Thank you!
7
3.86
(7 Votes)
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