promise all in promise all

var p1 = Promise.resolve(3);
var p2 = 1337;
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 100, "foo");
}); 

Promise.all([p1, p2, p3]).then(values => { 
  console.log(values); // [3, 1337, "foo"] 
});

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Celestriel 130 points

                                    // A simple promise that resolves after a given time
const timeOut = (t) =&gt; {
  return new Promise((resolve, reject) =&gt; {
    setTimeout(() =&gt; {
      if (t === 2000) {
        reject(`Rejected in ${t}`)
      } else {
        resolve(`Completed in ${t}`)
      }
    }, t)
  })
}

const durations = [1000, 2000, 3000]

const promises = []

durations.map((duration) =&gt; {
  promises.push(timeOut(duration)) 
})

// We are passing an array of pending promises to Promise.all
Promise.all(promises)
.then(response =&gt; console.log(response)) // Promise.all cannot be resolved, as one of the promises passed got rejected.
.catch(error =&gt; console.log(`Error in executing ${error}`)) // Promise.all throws an error.

Thank you! 10

4 (10 Votes)

MikeTeeVee 80 points

                                    var arr = [
  {subarr: [1,2,3]},
  {subarr: [4,5,6]},
  {subarr: [7,8,9]}
];
function processAsync(n) {
  return new Promise(function(resolve) {
    setTimeout(
      function() { resolve(n * n); },
      Math.random() * 1e3
    );
  });
}
Promise.all(arr.map(function(entity){
  return Promise.all(entity.subarr.map(function(item){
    return processAsync(item);
  }));
})).then(function(data) {
  console.log(data);
});

Thank you! 9

4 (9 Votes)

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