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loop array of objects

Phoenix Logan 
/* new options with IE6: loop through array of objects */

const people = [
  {id: 100, name: 'Vikash'},
  {id: 101, name: 'Sugam'},
  {id: 102, name: 'Ashish'}
];

// using for of
for (let persone of people) {
  console.log(persone.id + ': ' + persone.name);
}

// using forEach(...)
people.forEach(person => {
 console.log(persone.id + ': ' + persone.name);
});
// output of above two methods
// 100: Vikash
// 101: Sugam
// 102: Ashish


// forEach(...) with index
people.forEach((person, index) => {
 console.log(index + ': ' + persone.name);
});
// output of above code in console
// 0: Vikash
// 1: Sugam
// 2: Ashish
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IllusiveBrian 18110 points 

                                    const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => element.x);
console.log(newArray); // [100, 200, 300]

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IllusiveBrian 18110 points 

                                    const myArray = [{x:100}, {x:200}, {x:300}];

myArray.forEach((element, index, array) => {
    console.log(element.x); // 100, 200, 300
    console.log(index); // 0, 1, 2
    console.log(array); // same myArray object 3 times
});

3 (1 Votes)
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Awgiedawgie 440220 points 

                                    const myArray = [{x:100}, {x:200}, {x:300}];

const newArray= myArray.map(element => {
    return {
        ...element,
        x: element.x * 2
    };
});

console.log(myArray); // [100, 200, 300]
console.log(newArray); // [200, 400, 600]

4 (2 Votes)
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A-312 69370 points 

                                    let arr = [object0, object1, object2];

for (let elm of arr) {
  console.log(elm);
}

4 (3 Votes)
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Awgiedawgie 440220 points 

                                    const people = [
    {name: 'John', age: 23}, 
    {name: 'Andrew', age: 3}, 
    {name: 'Peter', age: 8}, 
    {name: 'Hanna', age: 14}, 
    {name: 'Adam', age: 37}];

const anyAdult = people.some(person => person.age >= 18);
console.log(anyAdult); // true

3 (1 Votes)
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