javascript every other element in array
let arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
// filter out all elements that are located at an even index in the array.
let x = arr.filter((element, index) => {
return index % 2 === 0;
})
console.log(x)
// [1, 3, 5, 7, 9]
4.25
8
// If you want every even index value:
var myArray = ["First", "Second", "Third", "Fourth", "Fifth"]
function every_other(array){
var temporaryArray = []
for (var i = 1; i < array.length; i += 2){ //Add two to i every iteration
temporaryArray.push(array[i]) //Add the element at index i to a temporary array
}
return temporaryArray.join(", ")
}
console.log(every_other(myArray)) //Expected output: Second, Fourth
Thank you!
8
4.25
(8 Votes)
0
3.67
3
// If you want every odd index value:
var myArray = ["First", "Second", "Third", "Fourth", "Fifth"]
function every_other(array){
var temporaryArray = []
for (var i = 0; i < array.length; i += 2){ //Add two to i every iteration
temporaryArray.push(array[i]) //Add the element at index i to a temporary array
}
return temporaryArray.join(", ")
}
console.log(every_other(myArray)) //Expected output: First, Third, Fifth
Thank you!
3
3.67
(3 Votes)
0
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