get unique values from array of objects javascript
const array =
[
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
const key = 'age';
const arrayUniqueByKey = [...new Map(array.map(item =>
[item[key], item])).values()];
console.log(arrayUniqueByKey);
/*OUTPUT
[
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
*/
// Note: this will pick the last duplicated item in the list.
Log in, to leave a comment
3.25
5
const unique = [...new Set(array.map(item => item.age))];
Thank you!
5
3.25
(4 Votes)
0
4.4
5
arr = [2, 2, 2, 1, 3, 3, 3,3, 4, 5];
arr = arr.sort().filter((item,i)=>!(arr[i] == arr[i+1] || arr[i-1]==arr[i]));
// this will remove all item which are repeating more then one
console.log(arr);
// [1, 4, 5]
Thank you!
5
4.4
(5 Votes)
0
0
0
function toUniqueArray(a){<br/> var newArr = [];<br/> for (var i = 0; i < a.length; i++) {<br/> if (newArr.indexOf(a[i]) === -1) {<br/> newArr.push(a[i]);<br/> }<br/> }<br/> return newArr;<br/>}<br/>var colors = ["red","red","green","green","green"];<br/>var colorsUnique=toUniqueArray(colors); // ["red","green"]
Thank you!
0
0
0
4.14
7
const data = [
{ group: 'A', name: 'SD' },
{ group: 'B', name: 'FI' },
{ group: 'A', name: 'MM' },
{ group: 'B', name: 'CO'}
];
const unique = [...new Set(data.map(item => item.group))]; // [ 'A', 'B']
Thank you!
7
4.14
(7 Votes)
0
4
6
//ES6
let array = [
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
];
array.map(item => item.age)
.filter((value, index, self) => self.indexOf(value) === index)
> [17, 35]
Thank you!
6
4
(6 Votes)
0
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