get an array with unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an array
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3.8
10
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);
console.log(unique); // ['a', 1, 2, '1']
Thank you!
10
0
0
4
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);
Thank you!
4
0
4
8
// usage example:
var myArray = ['a', 1, 'a', 2, '1'];
var unique = myArray.filter((v, i, a) => a.indexOf(v) === i);
// unique is ['a', 1, 2, '1']
Thank you!
8
0
3.5
6
import java.util.Random;
public class GenRandArray {
//Recommend reseeding within methods
static Random rand = new Random();
public static void fillInt( int[] fillArray ) {
//seeds the random for a new random each method call
rand.setSeed(System.currentTimeMillis());
for(int i = 0; i < fillArray.length; i++)
{
fillArray[i]= rand.nextInt();
/* for loop to check to make sure that none of the previous
numbers added are the same as the one just added. */
for (int j = 0; j < i; j++)
{
/* if so we need to redo the last random number by
moving i back one index to be re-set */
if (fillArray[i] == fillArray[j])
{
i--;
}
}
}
}
}
Thank you!
6
0
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