for of get index

for (const v of ['a', 'b', 'c']) {
  console.log(v)
}

// get index
for (const [i, v] of ['a', 'b', 'c'].entries()) {
  console.log(i, v)
}

4
6
IllusiveBrian 18110 points

                                    for (const [i, v] of ['a', 'b', 'c'].entries()) {
  console.log(i, v)
}

4 (6 Votes)
0
3.67
6
Awgiedawgie 440220 points

                                    for (const [i, v] of ['a', 'b', 'c'].entries()) {
  console.log(i, v)
}

3.67 (6 Votes)
0
4
9
Awgiedawgie 440220 points

                                    let array = ["foo", "bar"]

let low = 0; // the index to start at
let high = array.length; // can also be a number

/* high can be a direct access too
	the first part will be executed when the loop starts 
    	for the first time
	the second part ("i < high") is the condition 
    	for it to loop over again.
    the third part will be executen every time the code 
        block in the loop is closed.
*/ 
for(let i = low; i < high; i++) { 
  // the variable i is the index, which is
  // the amount of times the loop has looped already
  console.log(i);
  console.log(array[i]); 
} // i will be incremented when this is hit.

// output: 
/*
	0
    foo
    1
    bar
*/

4 (9 Votes)
0
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