filter array with unique objects javascript

const array =
  [
    { "name": "Joe", "age": 17 },
    { "name": "Bob", "age": 17 },
    { "name": "Carl", "age": 35 }
  ]

const key = 'age';

const arrayUniqueByKey = [...new Map(array.map(item =>
  [item[key], item])).values()];

console.log(arrayUniqueByKey);

   /*OUTPUT
       [
        { "name": "Bob", "age": 17 },
        { "name": "Carl", "age": 35 }
       ]
   */

 // Note: this will pick the last duplicated item in the list.

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Awgiedawgie 440220 points

                                    const data = [
  { group: 'A', name: 'SD' }, 
  { group: 'B', name: 'FI' }, 
  { group: 'A', name: 'MM' },
  { group: 'B', name: 'CO'}
];
const unique = [...new Set(data.map(item =&gt; item.group))]; // [ 'A', 'B']

Thank you! 6

3.67 (6 Votes)

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5

3

Phoenix Logan 186120 points

                                    //ES6
let array = [
  { &quot;name&quot;: &quot;Joe&quot;, &quot;age&quot;: 17 },
  { &quot;name&quot;: &quot;Bob&quot;, &quot;age&quot;: 17 },
  { &quot;name&quot;: &quot;Carl&quot;, &quot;age&quot;: 35 }
];
array.map(item =&gt; item.age)
  .filter((value, index, self) =&gt; self.indexOf(value) === index)

&gt; [17, 35]

Thank you! 3

5 (3 Votes)

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4.67

3

Awgiedawgie 440220 points

                                    const unique = [...new Set(array.map(item =&gt; item.age))];

Thank you! 3

4.67 (3 Votes)

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