check if number appears odd number of times in array javascript
// Find the odd int
function findOdd(A) {
return A.reduce((a, b) => a ^ b);
}
console.log(findOdd([20,1,-1,2,-2,3,3,5,5,1,2,4,20,4,-1,-2,5], 5)); // 5
console.log(findOdd([1,1,2,-2,5,2,4,4,-1,-2,5], -1)); // -1
console.log(findOdd([20,1,1,2,2,3,3,5,5,4,20,4,5], 5)); // 5
0
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function findOdd(A) {
let counts = A.reduce((p, n) => (p[n] = ++p[n] || 1, p), {});
return +Object.keys(counts).find(k => counts[k] % 2) || undefined;
}
Thank you!
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