unique numbers in array java
import java.util.ArrayList;
public class UniqueNumbersInArray {
public static void main(String[] args) {
int arr[] = { 4,5,5,4,5,6,5,8,4,7};
ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
int k = 0;
if (!uniqueArr.contains(arr[i])){
uniqueArr.add(arr[i]);
k++;
for (int j = i; j < args.length ; j++) {
if (arr[i]==arr[j]){
k++;
}
}
System.out.println(arr[i]);
System.out.println(k);
}
}
}
}
3.8
10
int [] arr = {1,1,1,2,2,2,3,3,3,4,4,5,5,6,7,8,};
for (int j= 0; j < arr.length; j++){
int count1 = 0; // to find out how many time value is appeared in the arry
for (int i = 0; i < arr.length; i++){
if(arr[i] == arr[j] ) {
// if(arr[i] == 1 ) { once boyleydi ikinci for gelince soldaki oldu
count1++; // arraydeki harfleri tek tek saymak icin
}
}
if(count1 == 1 ){
System.out.print(arr[j]+" ");// 6 7 8 uniqe
}
Thank you!
10
0
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