Leap year using conditional operator in java
// Leap year using conditional operator in java
import java.util.Scanner;
public class LeapYearExample
{
public static void main(String[] args)
{
long number, year, a;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter any year :");
year = sc.nextLong();
if(year != 0)
{
number = (year % 400 == 0)?(a = 1):((year % 100 == 0)?(a = 0):((year % 4 == 0)?(a = 1):(a = 0)));
if(number == 1)
{
System.out.println(year + " is a leap year");
}
else
{
System.out.println(year + " is not a leap year");
}
}
else
{
System.out.println("year zero does not exist ");
}
sc.close();
}
}
Are there any code examples left?
New code examples in category Java
-
Java 2022-03-27 21:35:04 Sort string array in case insensitive order and case sensitive order java
-
Java 2022-03-27 21:25:10 java -jar -l resources\es.porperties -i ejemplo.txt -o inject.bin
-
Java 2022-03-27 21:20:21 Debug & Fix a 2-Dimensional Array Java Console Application
-
Java 2022-03-27 20:40:19 TreeSet headSet(E toElement) method in java
-
Java 2022-03-27 19:30:06 close keyboard android
-
Java 2022-03-27 19:20:40 java measure execution time
-
Java 2022-03-27 19:10:06 how to add cardview support in android studio
-
Java 2022-03-27 18:55:08 android studio lower case letters on a button