findbyname in jpa

List<User> findByAgeGreaterThan(Integer age);List<User> findByAgeGreaterThanEqual(Integer age);

3.75
4
Phoenix Logan 186120 points

                                    List&lt;User&gt; findByAgeIn(Collection&lt;Integer&gt; ages);

3.75 (4 Votes)
0
3.33
6
Awgiedawgie 440215 points

                                    List&lt;User&gt; findByNameOrBirthDate(String name, ZonedDateTime birthDate);List&lt;User&gt; findByNameOrBirthDateAndActive(String name, ZonedDateTime birthDate, Boolean active);

3.33 (6 Votes)
0
3.75
9
A-312 69370 points

                                    List&lt;User&gt; findByNameContaining(String infix);

3.75 (8 Votes)
0
5
1
Awgiedawgie 440215 points

                                    List&lt;User&gt; findByAgeBetween(Integer startAge, Integer endAge);

5 (1 Votes)
0
4
2
Awgiedawgie 440215 points

                                    List&lt;User&gt; findByNameIsNot(String name);

4 (2 Votes)
0
4.2
5
Phoenix Logan 186120 points

                                    List&lt;User&gt; findTop3ByAge()

4.2 (5 Votes)
0
0
0
Krish 100200 points

                                    List&lt;User&gt; findByBirthDateAfter(ZonedDateTime birthDate);List&lt;User&gt; findByBirthDateBefore(ZonedDateTime birthDate);

0
0
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