find min number in java

                                     Scanner input = new Scanner(System.in);
        // Minimum And Maximum 
        int count = 0;
        int min = 0;
        int max = 0;
        boolean bugSolved = true;
		/* or we can use :
        int min = Integer.MAX_VALUE;
        int max = Integer.MIN_VALUE;
        */
		
        while (true){
            int cnt = count++;
            System.out.print("Enter Number #"+(cnt+1)+": ");
            boolean isValid = input.hasNextInt();
            if(isValid){
               int num = input.nextInt();
               /* if (bugSolved){
                   bugSolved = false;
                   min = num;
                   max = num;
               }  # Just remove this condition and 
               	boolean (bugSolved) at the top, if you use 
               	int min = Integer.MAX_VALUE and int max = 
                Integer.MIN_VALUE */
                if (num < min) {
                    min = num;
                }else if (num > max){
                    max = num;
                }
            }else{
                System.out.println("Invalid input..");
                break;
            }
            input.nextLine();
        }
        System.out.println("Min Number : " + min);
        System.out.println("Max Number : " + max);

                                    int[] arr = {2, 3, 4, 5, 6, 7, 8, 9,};
        int max = arr[0]; // max tanimliyorsun
        int min = arr[0];  // min tanimliyorsun

        for (int i = 0; i < arr.length; i++) {
            if (arr[i] > max){ 
// array's index are compared with each other,
// whichever is greater will be assigned to max
                max = arr[i];
            }
            if(arr[i] < min){ 
//array's index are compared with each other,
// whichever is smaller will be assigned to min
                min = arr[i];
            }
        }
        System.out.println(max); // 9
        System.out.println(min);  // 2