exception in thread "main" java.lang.indexoutofboundsexception: index 1 out of bounds for length 1

 0 means you are trying to access index 0 which is invalid, which in turn means the array is empty.
 String[] names = new String[0]; // thats the problem
 String[] names = new String[somelength];//this is true usage

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Philipxy 110 points

                                    Double[] sortedArray = new Double[array.length];

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Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 0 out of bounds for length 0 at Demo.main(Demo.java:5) Caused by: java.lang.ArrayIndexOutOfBoundsException: Index -17 out of bounds for length 23 ava.lang.ArrayIndexOutOfBoundsException: Index -2 out of bounds for length 0 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 5 out of bounds for length 5 at Main.main(Main.java:18) java.lang.ArrayIndexOutOfBoundsException: 0 Exception in thread "AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: Index 6 out of bounds for length 3 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 5 out of bounds for length 5 java.lang.ArrayIndexOutOfBoundsException: Index -1 out of bounds for length 4 java.lang.arrayindexoutofboundsexception: index 3 out of bounds for length 3 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 25 out of bounds for length 12 Exception in thread "Thread-4" java.lang.ArrayIndexOutOfBoundsException: Index 49 out of bounds for length 49 java.lang.ArrayIndexOutOfBoundsException: Index 5 out of bounds for length 5 java.lang.ArrayIndexOutOfBoundsException: length=0; 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