print reverse number
#include <stdio.h>
int main() {
int n, rev = 0, remainder;
printf("Enter an integer: ");
scanf("%d", &n);
while (n != 0) {
remainder = n % 10;
rev = rev * 10 + remainder;
n /= 10;
}
printf("Reversed number = %d", rev);
return 0;
}
3.25
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void printReverse(int n) {
if (n < 1) return;
cout << n << endl;
printReverse(n - 1);
}
printReverse(10); /// 10 9 8 7 6 5 4 3 2 1
Thank you!
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