cin.getline

string z,s;
 while (true)
    {
      cin>>z;
      s+=z;
      if(cin.peek()=='\n')
      break;
    }
................................
			OR\/
.................................
string s;
getline(cin,s);

4.33
6
Krish 100200 points

                                    // extract to string
#include <iostream>
#include <string>

int main ()
{
  std::string name;

  std::cout << "Please, enter your full name: ";
  std::getline (std::cin,name);
  std::cout << "Hello, " << name << "!\n";

  return 0;
}

4.33 (6 Votes)
0
4
5
Phoenix Logan 186125 points

                                    getline(cin, variable_name, '\n');

4 (5 Votes)
0
3
1
Phoenix Logan 186125 points

                                    cin>>n;
cin.ignore();
cin.getline(cin,string,'\n');

3 (1 Votes)
0
0
8
Awgiedawgie 440220 points

                                    getline(cin, variable_name);

0
0
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